calculate dy/dx of the forum at x = 5 and x = 3

*ahem*

Oh no. Now I'm distracted.

>calculate dy/dx of the forum at x = 5 and x = 3
>
>*ahem*


Where 'the forum' is a given function of a, b, j, k, d, r, and L.

also calculate partial dt/dy, partial dt/dx and partial d2t/dydx

it's been a while since I did differential equations..

It's been about 4 months for me, so I know all. Or not.

How do they get the chocolate chips into the cookies without the chocolate melting?

They don't.

Is that a new top?

That reminds me, does anyone remember that guy from that show? You know, it was in the Eighties and starred that man from that other thing on Channel 4. Remember? He used to wear that blue shirt. Or was it red? Hold on, was it on BBC2? Wait, he may have been a woman...

>also calculate partial dt/dy, partial dt/dx and partial d2t/dydx
>
>it's been a while since I did differential equations..

Okay, I'll make the assumption that the form can be expressed by these equations:

y = 2t^2 + t
x = t^3 + t

dt/dy = er, I give up....

well, dy/dt would be 4t + 1, so dt/dy would be the inverse of that.

how can I get a job sticking those stickers on apples?

do i need any special qualifications?

>do i need any special qualifications?

Yes, but you can only get those from a special school.

>That reminds me, does anyone remember that guy from that show? You know, it was in the Eighties and starred that man from that other thing on Channel 4. Remember? He used to wear that blue shirt. Or was it red? Hold on, was it on BBC2? Wait, he may have been a woman...

Yes, I remember...the dog chasing a llama falling through a bar, classic.

It was better on acid.

>>That reminds me, does anyone remember that guy from that show? You know, it was in the Eighties and starred that man from that other thing on Channel 4. Remember? He used to wear that blue shirt. Or was it red? Hold on, was it on BBC2? Wait, he may have been a woman...
>
>Yes, I remember...the dog chasing a llama falling through a bar, classic.
>
>It was better on acid.


*F/X: FORUM IMPLODES*

>well, dy/dt would be 4t + 1, so dt/dy would be the inverse of that.
I thout dy/dt was not the inverse of dt/dy. It is all so hazy now.

>>well, dy/dt would be 4t + 1, so dt/dy would be the inverse of that.
>I thout dy/dt was not the inverse of dt/dy. It is all so hazy now.
>

I'm pretty sure it is, think about it in terms of a graph. It makes sense.
Not that that is by any means a rigorous mathematical proof.

From distant memory, I think dy/dt is only the inverse of dt/dy up to the point where you resolve the differential, or something. Shit, I can't believe I'm even trying to work this out.

it's catching isn't it.

dy/dt x dt/dx = dy/dx

you're free to swap dx/dt over to dt/dx with a simple 1/function.

I'd like to buy a microwave if anyone's selling one.

>dy/dt x dt/dx = dy/dx

Yep, chain rule, isn't it?

>>dy/dt x dt/dx = dy/dx
>
>Yep, chain rule, isn't it?
>
>

Please stop bringing back the horror and torment of Maths and - because I was a fool - Further Maths A-levels (ended up only managing an E at AS level FM, by the way). I had almost successfully blocked out all memories of that until this thread started up. Aaaaaaack!

You will remember maths, you will remember. If I have to do it 5 days a week at degree level, then I shall inflict upon all others too.

>>dy/dt x dt/dx = dy/dx
>
>Yep, chain rule, isn't it?
>
>

2 points for you.

it works for partial derivatives too.

I too, thought I could get away from maths when I went to uni.

I do it three days a week now.

Oh no, I'm fucking tortured now. Somebody please remind me what a partial derivative is.

Is it the one with the curly d symbol:

_
/ \
_\
/ |
\_/

as opposed to the delta thing:
_
/ \
_\
/ |
\_/

Partial derivatives are differentiating a function of more than one variable, eg f(x,x,y) with respect to one of the variables while essential treating the other variables as constants. Yes, with "curly d"s.

>Partial derivatives are differentiating a function of more than one variable, eg f(x,x,y) with respect to one of the variables while essential treating the other variables as constants. Yes, with "curly d"s.

I did of course mean f(x,y,z)

So, Fermats last theorem, then. Thats the one that says that x^n + y^n =/= z^n if n is any greater than 2? Isn't it? As opposed to Laundromats last theorum which states that, in a public launderette, it is impossible to transfer washing from the washer to the dryer without at least some items of underwear falling to the floor.

>So, Fermats last theorem, then. Thats the one that says that x^n + y^n =/= z^n if n is any greater than 2? Isn't it? As opposed to Laundromats last theorum which states that, in a public launderette, it is impossible to transfer washing from the washer to the dryer without at least some items of underwear falling to the floor.

For any x, y, z, yes. And some bloke proved it by complicating it massively.

Buggery HTML formatting. You know what I mean.